# A container with a volume of 6 L contains a gas with a temperature of 400^o K. If the temperature of the gas changes to 570 ^o K without any change in pressure, what must the container's new volume be?

V_1/T_1=V_2/T_2=>V_2=V_1*(T_2/T_1)=> V_2=6*(570/400)=> V_2=8.55L