A container with a volume of 7 L contains a gas with a temperature of 360^o C. If the temperature of the gas changes to 540 ^o K without any change in pressure, what must the container's new volume be?

Jun 17, 2016

${V}_{f} = 5.97 L$

Explanation:

$\text{initial volume of gas :} {v}_{i} = 7 L$

$\text{initial temperature of gas :} {T}_{i} = {360}^{o} = 360 + 273 = {633}^{o} K$

$\text{final temperature of gas :} {540}^{o} K$

${V}_{i} / {T}_{i} = {V}_{f} / {T}_{f}$

$\frac{7}{633} = {V}_{f} / 540$

${V}_{f} = \frac{540 \cdot 7}{633}$

${V}_{f} = 5.97 L$