A container with a volume of $7 L$ $7 L$ contains a gas with a temperature of $490^{o} C$ $490^o C$ . If the temperature of the gas changes to $570^{o} K$ $570 ^o K$ without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-06-03T08:13:23

$V_{f} = 4.73 L$ $V_f=4.73" "L$

$V_{i} = 7 L$ $V_i=7" "L$

$T_{i} = 570^{o} C = 570 + 273 = 843^{o} K$ $T_i=570 ^o C=570+273=843 ^o K$

${the unit}^{o} C {must be converted to unit}^{o} K$ $"the unit "^o C" must be converted to unit "^o K"$

$T_{f} = 570^{o} K$ $T_f=570 ^o K$

$V_{f} = ?$ $V_f=?$

$\frac{V_{i}}{T_{i}} = \frac{V_{f}}{T_{f}}$ $V_i/T_i=V_f/T_f$

$\frac{7}{843} = \frac{V_{f}}{570}$ $7/843=V_f/570$

$V_{f} = \frac{570 \cdot 7}{843}$ $V_f=(570*7)/843$

$V_{f} = 4.73 L$ $V_f=4.73" "L$

A container with a volume of 7 L7L7 L contains a gas with a temperature of 490^o C490oC490^o C. If the temperature of the gas changes to 570 ^o K570oK570 ^o K without any change in pressure, what must the container's new volume be?