A container with a volume of #8 L# contains a gas with a temperature of #180^o K#. If the temperature of the gas changes to #360 ^o K# without any change in pressure, what must the container's new volume be?
1 Answer
The new volume is 16L.
Explanation:
Let's identify our known and unknown variables.
The first volume we have is
We can obtain the answer using Charles' Law which shows that there is a direct relationship between volume and temperature as long as the pressure and number of moles do not change.
The equation we use is:
The volume should have units of liters and the temperature must have units of Kelvins. In our case, both have good units!
Now rearrange the equation and plug in the given values
#V_2 = (T_2 * V_1)/(T_1)#
#V_2 = (360cancel("K") * "8 L") / (180 cancel("K"))#
#V_2 = "16 L"#
When using the Kelvin scale, you do not put the degree symbol. You just write K.