A container with a volume of #8 L# contains a gas with a temperature of #230^o C#. If the temperature of the gas changes to #340 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-02-03T16:09:14

The volume is #=5.41L#

We apply Charles' Law

#V_1/T_1=V_2/T_2#

#V_1=8 L#

#T_1=230+273=503K#

#T_2=340K#

#V_2=T_2/T_1*V_1#

#=340/503*8=5.41L#