# A cube of wood floating in water supports a 200-g mass resting on the center of its top face.when the mass removed the cube rises 2-cm.determine the volume of the cube? Ans: 1000 cm^3

Apr 22, 2018

${\text{1000 cm}}^{3}$

#### Explanation:

Let edge length of cube be $\text{x cm}$

Volume of water displaced by $\text{200 g}$ object is $2 {\text{x"^2\ "cm}}^{3}$

$\text{Mass of 200 g block = Mass of water displaced}$

$\text{200 g = V d}$

200 cancel"g" = "2x"^2cancel("cm"^3) × 1 cancel"g""/"cancel("cm"^3)

$x = \sqrt{\frac{200}{2}} = 10$

Volume of cube$= {\text{(edge length)"^3 = "(10 cm)"^3 = "1000 cm}}^{3}$