A dice is rolled, what is the probability of getting 1 and 6?

A. 1/6
B. 2/36
C. 1/36
D. 3/6

2 Answers
Mar 1, 2018

#2/36#

Explanation:

I assume that dice has been rolled twice. So, there could be 1 number on the top side each time.
I also assume that the numbers may or may not appear in given sequence.

probability of getting # 1# or #6# first time #=2/6#

Now since we have got either of six or one we need the other one now.

Examples are better for explaining. So, consider that 1 appeared on top now we need 6.
So probability of getting #6" is "1/6#.
Multiply both probabilities and we get #2/6×1/6=2/36#
(note we could have got 6 also first time but that doesn't hinder our calculation)

If we ask "What is the probability of rolling a 1 and then rolling a 6?", the answer is C #=1/36#

Explanation:

I'm going to run through what we're given and see if we can piece this together.

When we roll a single die, we're only going to get a single roll - we can't get both a 1 and a 6, which is what the question currently asks.

So what if we ask the question - What is the probability of rolling a 1 and then rolling a 6?

With this question, we have an answer that makes sense.

The probability of rolling a 1 is #1/6#. On the next roll, the probability of rolling a 6 is also #1/6#. Since these are independent events, we multiply to see the probability of rolling a 1 and then rolling a 6:

#1/6xx1/6=1/36#

If we ask the question What is the probability of rolling a 1 or a 6, we look at the number of ways we can meet the conditions #(=2)# over the number of ways a die can come up #(=6)#, and get:

#2/6# - but there is no option for this and so probably isn't the question being asked.