Question

A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15°C. How many gas particles are in this bubble?

Answer 1

Approx. `0.025xxN_A, N_A="Avogadro's Number"`

Explanation:

`n=(PV)/(RT)=(2.4*atmxx0.250*L)/(0.0821*L*atm*K^-1mol^-1xx288*K)=0.0254*mol`

What sort of gas would be in the bubble? Would this be the same as the gas in the gas bottle?