# A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15°C. How many gas particles are in this bubble?

Approx. $0.025 \times {N}_{A} , {N}_{A} = \text{Avogadro's Number}$
$n = \frac{P V}{R T} = \frac{2.4 \cdot a t m \times 0.250 \cdot L}{0.0821 \cdot L \cdot a t m \cdot {K}^{-} 1 m o {l}^{-} 1 \times 288 \cdot K} = 0.0254 \cdot m o l$