# A flower pot with a mass of 6.8kg is hanging by 4 wires that make an angle of 53° from the horizontal. What is the tension on each wire?

Nov 2, 2015

$\text{T"=20.8"N}$

#### Explanation:

The weight of the flower pot is supported by the tension in the 4 wires.

The vertical component of the tension will be $T \cos \left(90 - 53\right) = T \sin \left(53\right)$.

Since there are 4 wires, these will all support the weight $\text{W}$.

So we can write:

$W = 4 T \sin \left(53\right)$

The weight $W$ is given by:

$W = m g$

$\therefore T = \frac{W}{4 \sin \left(53\right)}$

$T = \frac{6.8 \times 9.8}{4 \times 0.8}$

$T = 20.8 \text{N}$