A flower pot with a mass of 6.8kg is hanging by 4 wires that make an angle of 53° from the horizontal. What is the tension on each wire?

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Answer 1 · 2015-11-02T22:37:43

#"T"=20.8"N"#

The weight of the flower pot is supported by the tension in the 4 wires.

The vertical component of the tension will be #Tcos(90-53)=Tsin(53)#.

Since there are 4 wires, these will all support the weight #"W"#.

So we can write:

#W =4Tsin(53)#

The weight #W# is given by:

#W=mg#

#:.T=(W)/(4sin(53))#

#T=(6.8xx9.8)/(4xx0.8)#

#T=20.8"N"#