# A gas sample has a volume of 225 mL at 122 kPa. What will its volume be at 101 kPa?

At constant $T$, ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$
Thus ${V}_{2}$ $=$ $\frac{{P}_{1} {V}_{1}}{P} _ 2$ $=$ $\frac{225 \cdot m L \times 122 \cdot k P a}{101 \cdot k P a}$ $=$ ??mL