A mixture contains 21.7 g NaCl 3.74 g KCI and 9.76 g LiCl. How many moles of NaCl are in the mixture?

1 Answer
Jul 13, 2018

0.371mol

Explanation:

n=m/(m_r)
m=21.7g
m_rNaCl=22.99+35.45=58.44g/(mol)

:. n= (21.7cancel(g))/(58.44cancel(g)/(mol))=0.371mol