A mixture of He, Ne, and Ar has a pressure of 7.85 atm. If the Ne has a mole fraction of 0.47 and Ar has a mole fraction of 0.23, what is the pressure of He?

1 Answer
Andrea B.
Apr 9, 2018

#p_(He) = 2,355 atm#

Explanation:

The sum of the mole fraction of the three components is 1, so the mole fraction of He is 1- 0,47-0,23 = 0,30
the partial pressure is given by the mole fraction multiplied for the total pressure.
#p_(He)= X_(He) xx P_t= 0,3 xx 7,85 atm =2,355 atm #

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