Question

A parachutist falls freely until he reaches a velocity of 56m/s. He then opens his parachute and slows to 12m/s in 32s. What is his average acceleration during these 32s?

Answer 1

`11/8 m/s^2`

Explanation:

Average acceleration is calculated by the following equation:

`a=(v_f-v_i)/t`

In this case, `v_f=56`, `v_i=12` and `t=32`. Simply plug into the equation:

`a=(56-12)/32=11/8`

Units for acceleration is `m/s^2`