Question

A particle start from rest moved with constant acceleration for 15second. if it cover s1 distance in first 5second then distance s2 in next 10second ,then find the relation between s1 and s2?

Answer 1

`s_1=0.5625s_2`

Explanation:

We use the kinematic expression
`s=ut+1/2at^2`
The particle starts from rest. Therefore, this expression reduces to
`s=1/2at^2`

From the given data, distance moved in first `15s`
`s(15)=s_1=1/2xxaxx15^2`
`=>s_1=112.5a` ........(1)

and distance moved in `25s`
`s(25)=1/2xxaxx25^2`
Therefore, distance moved in next `10s`

`s_2=1/2xxaxx25^2-1/2xxaxx15^2`
`=>s_2=1/2xxaxx(25-15)(25+15)`
`=>s_2=200a` ......(2)
Dividing (1) with (2) we get
`s_1/s_2=(112.5a)/(200a)`
`=>s_1=0.5625s_2`