A patient with respiratory alkalosis has a blood plasma pH of 7.58. What is the #[H_3O^+]# of the blood plasma?

1 Answer
Nov 29, 2016

Answer:

#pH=-log_10[H_3O^+]#. Here #[H_3O^+]# #=# #10^(-7.58)*mol*L^-1#

Explanation:

Here #[H_3O^+]# #=# #10^(-7.58)*mol*L^-1=2.6xx10^-8*mol*L^-1#.

#[HO^-]#, so I presume, is elevated with this condition. What is #[HO^-]# here? What do you think it should be?