# A polygon has 6 sides. How would I find the measure of each exterior and interior angle?

Dec 24, 2015

Use the interior sum formula ...

#### Explanation:

interior sum $= \left(6 - 2\right) \times 180 = {720}^{o}$

So, each interior angle $= {720}^{o} / 6 = {120}^{o}$

The sum of the exterior angles of any polygon is ${360}^{o}$

Each exterior angle $= {360}^{o} / 6 = {60}^{o}$

hope that helped