A projectile is launched at an angle of 30 to the horizontal with a speed of 30 m/s. How does the horizontal component of its velocity 1.0 s after launch compare with its horizontal component of velocity 2.0 s after launch?

1 Answer
Jan 2, 2018

Component of velocity in horizontal direction #= 15sqrt3m/s#

Explanation:

In projectile motion, horizontal component of velocity remains constant as there is no acceleration in horizontal direction.

So, Component of velocity in horizontal direction #= vcostheta#

Component of velocity in horizontal direction #= 30xxcos30#

Component of velocity in horizontal direction #= 15sqrt3m/s#

And, horizontal component of velocity# 1.0 s# after launch is equal to its horizontal component of velocity #2.0 s# after launch.