# A projectile is launched with an initial speed of Vo at an angle θ above the horizontal. It lands at the same level from which it was launched. What was the average velocity between launch and landing? Explain please because I can't understand this.

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Typical flight of a projectile is as shown in the picture above.

In the problem it is given that initial velocity

This velocity can be resolved into its

Component along

Component along

We also know that both

Maximum height is achieved due to

This component of the velocity decreases due to action of gravity. Becomes zero at the maximum height point. Then increases due to gravity and becomes equal to initial

Let

It is given that "It lands at the same level from which it was launched", means that displacement in the

If we ignore air resistance,

Now to find the Resultant Average velocity we need to add both vectors along

Hence,

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Average velocity = 0

Average speed =

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Average velocity = displacement# / time = 0 since the displacement is zero. The initial and final positions are the same.

Time to reach maximum height after launch =

Time to land from maximum height is the same. Therefore, the total time from launch to land is

Maximum height =

Total distance traveled= launch to

Average speed = total distance /total time

Average speed =

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