# A projectile is shot at a velocity of # 1 m/s# and an angle of #pi/4 #. What is the projectile's peak height?

##### 1 Answer

Mar 10, 2018

If the projectile is shot at a velocity of

The maximum height will occur when the vertical component of velocity equals

We now need to find a kinematic equation that will make sense for this problem.

#v_y^2 = v_(y_0)^2 + 2a_y(Deltay)#

We will be solving for

#0 = 1/2 + 2(-9.8)Deltay#

#Delta y = 0.026# meters, or#2.6# cm.

Hopefully this helps!