A projectile is shot at an angle of pi/4  and a velocity of  16 m/s. How far away will the projectile land?

$\frac{128}{5}$
This answer is based on if $g = 10$
The vertical($v e r$) and horizontal($h r z$) velocity($V$) are both $16 \cdot \frac{\sqrt{2}}{2} = 8 \sqrt{2}$
Next we calculate the time($T$) it takes to go up and down
We can use how long it take till the vertical speed equals $0$ to get the time, $T = \frac{v e r V}{g} = 8 \frac{\sqrt{2}}{10} = 8 \frac{\sqrt{2}}{5}$
Now we can calculate the distance $D = h r z V \cdot T = 8 \sqrt{2} \cdot 8 \frac{\sqrt{2}}{5} = \frac{128}{5}$