# A projectile is shot at an angle of pi/6  and a velocity of  2 m/s. How far away will the projectile land?

The projectile will fall $0.35 m$ far.
Find the moment when the projectile fall and use the vertical equation $s \left(y\right) = v t - \frac{1}{2} a {t}^{2} = 0$; $t \left(f a l l\right) = 2 \frac{v}{g} = \frac{2 \cdot v \sin 30}{g} = 0.2 s$ and subsitute this value in the horizontal equation
s(t)=vt=(vcos30°)*0.2=0.35m