A projectile is shot at an angle of $pi/6$ and a velocity of $4 m/s$ . How far away will the projectile land?

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Answer 1 · 2016-05-12T12:55:49

$x_m=1.41" m"$

$x_m=(v_i^2*sin 2 alpha)/g$

$x_m=(4^2*sin (2*pi/6))/(9.81)$

$x_m=16*sin(pi/3)/(9.81)$

$x_m=(16*0.866)/(9.81)$

$x_m=1.41" m"$

A projectile is shot at an angle of pi/6 pi/6 and a velocity of 4 m/s 4 m/s. How far away will the projectile land?