# A projectile is shot from the ground at an angle of #(5 pi)/12 # and a speed of #2 m/s#. Factoring in both horizontal and vertical movement, what will the projectile's distance from the starting point be when it reaches its maximum height?

##### 1 Answer

The distance is

#### Explanation:

The initial speed is

The angle is

The equation of the trajectory of the projectile is

At the maximum height

Therefore,

and

Plugging this value of

The acceleration due to gravity is

Therefore,

The distance from the starting point to the greatest height is