A real polynomial P(x) is the product of real linear and real quadratic factors. Can you that if a real quadratic factor has one zero, a+bi, then the other zero must be the complex conjugate, a-bi?
Hint: Let the quadratic be alphax^2 + betax + gamma and use the properties of complex conjugates
Hint: Let the quadratic be
2 Answers
See below.
Explanation:
where
but
and
So if
concluding
Another version.
If
or
The feasible solution is
because
with both
So if
Use the quadratic formula...
Explanation:
If one of the real quadratic factors is:
alphax^2+betax+gamma
then using the quadratic formula, it has zeros:
(-beta+-sqrt(beta^2-4alphagamma))/(2alpha)
If
Otherwise,
sqrt(beta^2-4alphagamma) = (sqrt(4alphagamma-beta^2))i
resulting in a complex conjugate pair of non-real zeros.