Question

A right triangle has a side of `1` `m` and a hypotenuse of `2sqrt7` `m`. What is the value of the other side?

Answer 1

Other side is `3sqrt3`

Explanation:

According to Pythagoras theorem, in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of other two sides.

Here as hypotenuse is `2sqrt7` `m.`, its square is `2sqrt7xx2sqrt7=4xx7=28`. As one side is `1` `m.` and its square is `1`

the square of the other side must be `28-1=27`.

Hence other side is `sqrt27=sqrt(3xx3xx3)=3sqrt3`