A right triangle has a side of $1$ $m$ and a hypotenuse of $2sqrt7$ $m$ . What is the value of the other side?

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Answer 1 · 2016-07-27T07:36:01

Other side is $3sqrt3$

According to Pythagoras theorem, in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of other two sides.

Here as hypotenuse is $2sqrt7$ $m.$ , its square is $2sqrt7xx2sqrt7=4xx7=28$ . As one side is $1$ $m.$ and its square is $1$

the square of the other side must be $28-1=27$ .

Hence other side is $sqrt27=sqrt(3xx3xx3)=3sqrt3$

A right triangle has a side of 11 mm and a hypotenuse of 2sqrt72sqrt7 mm. What is the value of the other side?