A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of $15/7$ , $3/5$ , and $3$ , respectively. What is the rectangle's area?

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Answer 1 · 2016-03-18T17:40:21

I have taken you to a point where you can finish it off!

Tony B Tony B

Using Pythagoras

Area of rectangle = 3B $= 3xxsqrt( (15/7)^2-(3/5)^2)$

Using the property of $a^2-b^2 = (a-b)(a+b)$

$"Area "=3xxsqrt((15/7-3/5)(15/7+3/5))$

I will let you finish this off!

A right triangle has sides A, B, and C. Side A is the hypotenuse and side B is also a side of a rectangle. Sides A, C, and the side of the rectangle adjacent to side B have lengths of 15/7 15/7 , 3/5 3/5 , and 3 3 , respectively. What is the rectangle's area?