Question

A sample of an ideal gas has a volume of 2.26 L at 289 K and 1.03 atm. How do you calculate the pressure when the volume is 1.64 L and the temperature is 308 K?

Answer 1

`(P_1V_1)/T_1=(P_2V_2)/T_2`, given a constant quantity of gas.

Explanation:

And thus `P_2=(P_1V_1)/T_1xxT_2/V_2`

`=` `(2.26*Lxx1.03*atm)/(289*K)xx(308*K)/(1.64*L)` `=` `??atm`