# A sample of an ideal gas has a volume of 2.26 L at 289 K and 1.03 atm. How do you calculate the pressure when the volume is 1.64 L and the temperature is 308 K?

$\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$, given a constant quantity of gas.
And thus ${P}_{2} = \frac{{P}_{1} {V}_{1}}{T} _ 1 \times {T}_{2} / {V}_{2}$
$=$ $\frac{2.26 \cdot L \times 1.03 \cdot a t m}{289 \cdot K} \times \frac{308 \cdot K}{1.64 \cdot L}$ $=$ ??atm