Question

A sample of argon gas at 520 mm Hg expands from 0.150 L to 0.300 L. If the temperature remains constant, what is the final pressure in mm Hg?

Answer 1

`260` `"mm Hg"`

Explanation:

To solve this problem, we can use the pressure-volume relationship of gases, illustrated by Boyle's law:

`P_1V_1 = P_2V_2`

Since we're trying to find the final pressure (`P_2`), let's rearrange the equation to solve for `P_2`:

`P_2 = (P_1V_1)/(V_2)`

Plugging in known values, we have

`P_2 = ((520"mm Hg")(0.150cancel("L")))/(0.300cancel("L")) = color(red)(260` `color(red)("mm Hg"`

The final pressure is thus `260` millimeters mercury.