# A sample of argon gas is cooled and its volume went from 380 mL to 250 mL. If its final temperature was -55° C, what was its original temperature?

##### 1 Answer

Jun 27, 2014

1) Convert -55 °C to Kelvin and you get 273 + (-55) = 218 K . At this temperature the volume of the gas is 250 mL.

2) At Temperature

Remember that you have to plug into the equation in a very specific way. The temperatures and volumes come in connected pairs and you must put them in the proper place.

Using Charles law equation;

plug in the values;

380 mL /

Cross-multiply and divide:

380 mL x 218 K = 250 mL x

82840 mL K = 250 mL x