A sample of argon gas is cooled and its volume went from 380 mL to 250 mL. If its final temperature was -55° C, what was its original temperature?
1 Answer
Jun 27, 2014
1) Convert -55 °C to Kelvin and you get 273 + (-55) = 218 K . At this temperature the volume of the gas is 250 mL.
2) At Temperature
Remember that you have to plug into the equation in a very specific way. The temperatures and volumes come in connected pairs and you must put them in the proper place.
Using Charles law equation;
plug in the values;
380 mL /
Cross-multiply and divide:
380 mL x 218 K = 250 mL x
82840 mL K = 250 mL x