# A sample of gas has a mass of 0.565 g. Its volume is 117 mL at a temperature of 95 C and a pressure of 749 mm Hg. How would you find the molar mass of the gas?

$\text{Molar mass}$ $\cong$ $150 \cdot g \cdot m o {l}^{-} 1$.
From the Ideal Gas equation, $n = \frac{P V}{R T}$, where, $n = \text{Mass"/"Molar mass}$.
And thus "Molar mass "=("Mass"xxRT)/(PV)
=(0.565*gxx0.0821*L*atm*K^-1*mol^-1xx368*K)/((749*mm*Hg)/(760*mm*Hg*atm^-1)xx0.117*L)=???g*mol^-1