Question

A sample of gas has a volume of 12 L and a pressure of 1.0 atm. If the pressure of gas is increased to 2.0 atm, what is the new volume of the gas? Temperature and moles are constant.

i do not understand the formula.

Answer 1

The new volume of the gas will be `6 \ "L"`.

Explanation:

Since the temperature and the amount of moles are constant, we have to use Boyle's law here, which states that

`Pprop1/V`

or

`P_1V_1=P_2V_2`

Since we need to solve for the second volume, we can rearrange the equation into

`V_2=(P_1V_1)/P_2`

Plugging in the given values, we get

`V_2=(1cancel"atm"*12 \ "L")/(2cancel"atm")`

`<=>V_2=6 \ "L"`

So, the new volume of the gas will be `6` liters.