A sample of gas in a flexible sided container has a volume of (3.100x10^-2) L when the temperature is (3.540x10^2) OC. The temperature is changed to (8.42x10^2)OC. What is the new volume of the gas assuming no change in pressure?

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Answer 1 · 2017-04-29T06:22:36

We use old Charles' Law which holds that #VpropT# under conditions of constant pressure. Temperature is specified on the #"Absolute scale"#.

Since #V/T=k#, where #k# is a constant, then #V_1/T_1=V_2/T_2#.

And so we solve for #V_2=V_1/T_1xxT_2#, where........

#T_1=627# #K#; #T_2=1115# #K, V_1=0.031*L#.

And #V_2=(0.031*L)/(627*K)xx1115*K#

And so the volume almost doubles..............