# A sample of gas in a flexible sided container has a volume of (3.100x10^-2) L when the temperature is (3.540x10^2) OC. The temperature is changed to (8.42x10^2)OC. What is the new volume of the gas assuming no change in pressure?

Apr 29, 2017

We use old Charles' Law which holds that $V \propto T$ under conditions of constant pressure. Temperature is specified on the $\text{Absolute scale}$.

#### Explanation:

Since $\frac{V}{T} = k$, where $k$ is a constant, then ${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$.

And so we solve for ${V}_{2} = {V}_{1} / {T}_{1} \times {T}_{2}$, where........

${T}_{1} = 627$ $K$; ${T}_{2} = 1115$ $K , {V}_{1} = 0.031 \cdot L$.

And ${V}_{2} = \frac{0.031 \cdot L}{627 \cdot K} \times 1115 \cdot K$

And so the volume almost doubles..............