A sample of gas X occupies 10#m^3# at the pressure of 120 kPa. If the volume of the sample is 3#m^3#, what is the new pressure of the gas?

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Answer 1 · 2017-01-21T03:16:43

The new pressure is 400 kPa

To solve this problem use Boyle's law.

As the volume decreases the pressure increases. This means that the new pressure will be greater than the original pressure.

#V_1 xx P_1 = V_2 xx P_2#

# V_1 = 10m^3#
# P_1 = 120 kPa#
#V_2 = 3m^3#
# P_2 = ?#

Putting these values into the equation gives.

# 10m^3 xx 120 kPa = 3m^3 xx ?#

Dividing both sides by # 3m^3# gives

# (10m^3 xx 120kPa)/(3m^3) = (3m^3 xx ?)/(3m^3)# This gives

400 kPa = ?

The unknown is 400 kPa.