A sample of gas X occupies 10m^3 at the pressure of 120 kPa. If the volume of the sample is 3m^3, what is the new pressure of the gas?

Jan 21, 2017

The new pressure is 400 kPa

Explanation:

To solve this problem use Boyle's law.

As the volume decreases the pressure increases. This means that the new pressure will be greater than the original pressure.

${V}_{1} \times {P}_{1} = {V}_{2} \times {P}_{2}$

${V}_{1} = 10 {m}^{3}$
${P}_{1} = 120 k P a$
${V}_{2} = 3 {m}^{3}$
 P_2 = ?

Putting these values into the equation gives.

 10m^3 xx 120 kPa = 3m^3 xx ?

Dividing both sides by $3 {m}^{3}$ gives

 (10m^3 xx 120kPa)/(3m^3) = (3m^3 xx ?)/(3m^3) This gives

400 kPa = ?

The unknown is 400 kPa.