A sample of gas X occupies 10#m^3# at the pressure of 120 kPa. If the volume of the sample is 3#m^3#, what is the new pressure of the gas?

1 Answer

Answer:

The new pressure is 400 kPa

Explanation:

To solve this problem use Boyle's law.

As the volume decreases the pressure increases. This means that the new pressure will be greater than the original pressure.

#V_1 xx P_1 = V_2 xx P_2#

# V_1 = 10m^3#
# P_1 = 120 kPa#
#V_2 = 3m^3#
# P_2 = ?#

Putting these values into the equation gives.

# 10m^3 xx 120 kPa = 3m^3 xx ?#

Dividing both sides by # 3m^3# gives

# (10m^3 xx 120kPa)/(3m^3) = (3m^3 xx ?)/(3m^3)# This gives

400 kPa = ?

The unknown is 400 kPa.