A sample of glass that has a mass of 6.0 g gives off 12 J of heat. If the temperature of the sample changes by 4.0°C during this change, what is the specific heat of the glass?

1 Answer
Dec 18, 2016

Answer:

#0.50 J/(g^oC) #

Explanation:

To obtain the specific heat of that glass, let's use the equation below:
http://slideplayer.com/slide/4758097/

Based on the information you've provided, we know the following variables:

#DeltaT# = #4^oC#
#Q# = 12 J
#m# = #6.0g#

All we have to do is rearrange the equation to solve for #C#. This can be accomplished by dividing both sides by #m# and #Delta T# to get #C# by itself like this:

#C = Q/(DeltaTxxm)#

Now, we just plug in the known values:

#C = (12J)/(4^oC"xx6.0g)#

#C = 0.50J/(gxx^oC) #