# A sample of glass that has a mass of 6.0 g gives off 12 J of heat. If the temperature of the sample changes by 4.0°C during this change, what is the specific heat of the glass?

Dec 18, 2016

$0.50 \frac{J}{{g}^{o} C}$

#### Explanation:

To obtain the specific heat of that glass, let's use the equation below:

Based on the information you've provided, we know the following variables:

$\Delta T$ = ${4}^{o} C$
$Q$ = 12 J
$m$ = $6.0 g$

All we have to do is rearrange the equation to solve for $C$. This can be accomplished by dividing both sides by $m$ and $\Delta T$ to get $C$ by itself like this:

$C = \frac{Q}{\Delta T \times m}$

Now, we just plug in the known values:

C = (12J)/(4^oC"xx6.0g)

$C = 0.50 \frac{J}{g {\times}^{o} C}$