# A sample of H_2O with a mass of 46.0 grams has a temperature of -58.0°C. How many joules of energy are necessary to heat the ice to 0°C?

## Use 2.1 J/g°C for the specific heat of ice.

May 22, 2016

5496.1 J

#### Explanation:

$q = m \times \Delta T \times c$

$q$ - amount of heat
$m$ - mass
$c$ - specific heat capacity
$\Delta T$ - Temperature difference

Given:

$\text{m = 46 g}$

$\text{T = -58"^@"C}$

$c = \text{2.06 J/g"cdot""^@"C}$ (You have to look this up)

I recommend drawing the diagram of ice melting.

q = (46.0cancel("g")) xx [0 - (-58)cancel(""^@"C")] xx (2.06 J/(cancel("g") cdot cancel(""^@"C"))) = "5496.1 J"