Question

A sample that contains 3.66 mol of a gas at 265 K has a pressure of 1.09 atm. What is the volume?

Answer 1

The volume of the gas is 73.1 L.

Explanation:

This question requires the ideal gas law. The equation for the ideal gas law is `PV=nRT`, where `P` is pressure, `V` is volume, `n` is moles, `R` is the gas constant, and `T` is the temperature in Kelvins.

Given/Known
`P="1.09 atm"`
`n="3.66 moles gas"`
`R=0.082057338("L·atm")/("K·mol")`
https://en.m.wikipedia.org/wiki/Gas_constant
`T="265 K"`

Unknown
`V`

Solution
Rearrange the equation to isolate volume. Substitute the known values into the equation and solve.

`PV=nRT`

`V=(nRT)/P`

`V=(3.66cancel"mol"·0.082057338("L"·cancel("atm"))/(cancel("K")·cancel("mol"))·265cancel"K")/(1.09cancel"atm")="73.1 L of gas"` rounded to three significant figures