A sample that contains 3.66 mol of a gas at 265 K has a pressure of 1.09 atm. What is the volume?

1 Answer
Mar 11, 2016

Answer:

The volume of the gas is 73.1 L.

Explanation:

This question requires the ideal gas law. The equation for the ideal gas law is #PV=nRT#, where #P# is pressure, #V# is volume, #n# is moles, #R# is the gas constant, and #T# is the temperature in Kelvins.

Given/Known
#P="1.09 atm"#
#n="3.66 moles gas"#
#R=0.082057338("L·atm")/("K·mol")#
https://en.m.wikipedia.org/wiki/Gas_constant
#T="265 K"#

Unknown
#V#

Solution
Rearrange the equation to isolate volume. Substitute the known values into the equation and solve.

#PV=nRT#

#V=(nRT)/P#

#V=(3.66cancel"mol"·0.082057338("L"·cancel("atm"))/(cancel("K")·cancel("mol"))·265cancel"K")/(1.09cancel"atm")="73.1 L of gas"# rounded to three significant figures