# A solution of NaOH has a concentration of 5.51*10^-3 M. What is the pH of this solution?

$p H = 11.74$
We know that $p H + p O H = 14$ for water at $298 K$.
$p O H = - {\log}_{10} 5.51 \times {10}^{- 3}$ $=$ $2.26$
pH=14-2.26=??