# A sound has speed of 330m/s and frequency of 50Hz what is the possible distance between 2 points on wave that have phase difference of 60°?

Jun 25, 2018

Any 2 points on wave that have phase difference of 60° are separated by a distance of 1.1 m.

#### Explanation:

The wavelength of this wave is

$\lambda = \frac{v}{f} = \frac{330 \frac{m}{\cancel{s}}}{\frac{50}{\cancel{s}}} = 6.6 m$

Since ${60}^{\circ} \text{ is } \frac{1}{6} t h$ of the total wavelength,

The possible distance between 2 points on wave that have phase difference of 60° = 6.6 m * 1/6 = 1.1 m

I hope this helps,
Steve