A sound has speed of 330m/s and frequency of 50Hz what is the possible distance between 2 points on wave that have phase difference of 60°?

1 Answer
Jun 25, 2018

Answer:

Any 2 points on wave that have phase difference of 60° are separated by a distance of 1.1 m.

Explanation:

The wavelength of this wave is

#lambda = v/f = (330 m/cancel(s))/(50/cancel(s)) = 6.6 m#

Since #60^@ " is " 1/6 th# of the total wavelength,

The possible distance between 2 points on wave that have phase difference of #60° = 6.6 m * 1/6 = 1.1 m#

I hope this helps,
Steve