A spring with a constant of $7 (kg)/s^2$ is lying on the ground with one end attached to a wall. An object with a mass of $2 kg$ and speed of $8 m/s$ collides with and compresses the spring until it stops moving. How much will the spring compress?

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Answer 1 · 2018-05-22T06:17:11

The compression is $=4.28m$

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The spring constant is $k=7kgs^-2$

The kinetic energy of the object is

$KE=1/2m u^2$

The mass is $m=2kg$

The speed is $u=8ms^-1$

$KE=1/2*2*(8)^2=64J$

This kinetic energy will be stored in the spring as potential energy.

$PE=64J$

So,

$1/2kx^2=64$

$x^2=(128)/(7)=18.29m^2$

$x=sqrt(18.29)=4.28m$

A spring with a constant of 7 (kg)/s^27 (kg)/s^2 is lying on the ground with one end attached to a wall. An object with a mass of 2 kg2 kg and speed of 8 m/s8 m/s collides with and compresses the spring until it stops moving. How much will the spring compress?