A student walks and jogs to college each day. The student averages 5 km/h walking and 9 km/h jogging. The distance from home to college is 8 km, and the student makes the trip in 1 hour. How far does the student jog?

1 Answer
Feb 7, 2016

Answer:

6.75 km

Explanation:

Let #x# be the duration spent jogging.

Since the total travel duration is 1 hour, #1 - x# is the duration spent walking

#d = st#

The distance covered by jogging is

#=> d_j = 9x#

Meanwhile, the distance covered by walking is

#d_w = 5(1 - x)#

Since the total distance covered is 8 km, we have

#=> 9x + 5(1 - x) = 8#

#=> 9x + 5 - 5x = 8#

#=> 4x = 3#

#=> x = 3/4#

We want the distance covered by jogging,

#d_j = 9x#

#d_j = 9(3/4)#

#d_j = 27/4 = 6 3/4 = 6.75#