#A# takes 6 days less than the time taken by #B# to finish a piece of work. If both #A# and #B# together can finish it in 4 days, how many days will #B# take to finish the work?

1 Answer
Dec 3, 2016

We call the time it takes for B to finish the piece of work #x#.

For problems like these, we must consider how much work can be done in one day.

#1/x + 1/(x- 6) = 1/4#

#(x - 6)/(x(x - 6)) + x/(x(x - 6)) = 1/4#

#4(x - 6 + x) = x^2 - 6x#

#4(2x- 6) = x^2 - 6x#

#8x - 24 = x^2 - 6x#

#0 = x^2 - 14x + 24#

#0 = (x- 12)(x - 2)#

#x = 12 and 2#

If the time it takes #B# is #2# days, then the time it takes #A# is #-4# days, which has no sense.

Therefore, it would take #B# a period of #12# days to finish the job.

Hopefully this helps!