A transverse wave is given by the equation #y=y_0 sin 2pi(ft-x/lambda)# The maximum particle velocity will be #4# times the wave velocity if, A. #lambda =(pi y_0)/4# B.#lambda =(pi y_0)/2# C.#lambda =pi y_0# D.#lambda =2 pi y_0# ?
1 Answer
Mar 16, 2018
Explanation:
Comparing the given equation with
amplitude of particle motion is
Now,maximum particle velocity i.e maximum velocity of S.H.M is
And,wave velocity
Given condition is
so,
or,