A water falls is approximately 90m high. Assume that all of the potential energy possessed by the water at the top is completely converted to heat energy.What will be the temperature difference between the water at the top and at the bottom of the falls?

1 Answer
Jane
Feb 3, 2018

Well,if such happens to be so,you can equate total potential energy #90 m# above the bottom of the falls to the heat energy.

So,we can write, #mgh = ms d theta# where, #d theta# is the temperature difference between the top and bottom of the water,and #s# is the specific heat of water.

Given, #s=90 m=9000 cm# and #s# for water is #1 C g^-1 degree C^-1#

So, #d theta=(gh)/s = (981*9000)/1 =8829000=88.29 *10^5 degree C#

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