# A250. mL sample of gas at 1.00 atm and 20 degrees Celsius has the temperature increased to 40 degrees Celsius and the volume increased to 500. mL. What is the new pressure?

Dec 10, 2016

$\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$
$\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$, given a constant quantity of gas.
And thus, $\frac{{P}_{1} \times {V}_{1} \times {T}_{2}}{{V}_{2} \times {T}_{1}} = {P}_{2}$, even given this format, we can see the problem is dimensionally sound. We do need to use $\text{absolute temperature.}$
${P}_{2} = \frac{1.00 \cdot a t m \times 250 \cdot m L \times 313 \cdot K}{500 \cdot m L \times 293 \cdot K} \cong \frac{1}{2} \cdot a t m .$