A250. mL sample of gas at 1.00 atm and 20 degrees Celsius has the temperature increased to 40 degrees Celsius and the volume increased to 500. mL. What is the new pressure?

1 Answer
Dec 10, 2016

Answer:

#(P_1V_1)/T_1=(P_2V_2)/T_2#

Explanation:

#(P_1V_1)/T_1=(P_2V_2)/T_2#, given a constant quantity of gas.

And thus, #(P_1xxV_1xxT_2)/(V_2xxT_1)=P_2#, even given this format, we can see the problem is dimensionally sound. We do need to use #"absolute temperature."#

#P_2=(1.00*atmxx250*mLxx313*K)/(500*mLxx293*K)~=1/2*atm.#