About 40 J is required to push a crate 4 m across a floor. If the push is in the same direction as the motion of the crate, what is the force on the crate?

1 Answer
Dec 4, 2015

Answer:

I found #F=10N#

Explanation:

Considering no friction, the enrgy is used up entirely to move the crate in the form of work done on the system and it will be:
#W=vecF*vecd=F*d*cos(theta)=#
enter image source here
#40=F*4#
rearranging:
#F=40/4=10N#