# About Charles's Law I have a confusion?

##### 1 Answer

The equation for **Charles's law** is

#ulbar(|stackrel(" ")(" "(T_1)/(V_1) = (T_2)/(V_2)" ")|)" "# (constant pressure and quantity of gas)

The problem says that the **volume** of the gas increases by **temperature** degree it rises.

If we make the final temperature

#T_2 = T_1 +-1#

Or

#(T_1)/(V_1) = (T_1+-1)/(V_2)#

Solving for the final volume,

#V_2 = V_1 +-(V_1)/(T_1)#

The temperature

#color(red)(ulbar(|stackrel(" ")(" "V_2 = V_1 +-(1/273)V_1" ")|)# (the units canceled out when we solved for

#V_2# )

Or, in words, **the final volume is equal to the original volume plus or minus #1/273# times the original volume**.