According to the equations below, what is the conjugate base of #HCO_3^-# ?
#H_2CO_3(aq) + H_2O (l) rightleftharpoons HCO_3^(-) (aq) + H_3O^(+)(aq)#
#HCO_3^(-)(aq) + H_2O(l) rightleftharpoons CO_3^(2-)(aq) + H_3O^(+)(aq)#
The conjugate base of
To find the conjugate base of ANY acid, all you have to do is remove a proton, and conserve mass and charge; simply take
What is the conjugate acid of
It seems I have asnwered this before.