# After burning 1.5g of some gas, 4.4g of CO2 and 2.7g of H2O were produced. What is this gas if at STP 1L of this gas weighs 1.34g?

##### 1 Answer

**ETHANE**

#### Explanation:

Since the gas on burning produces

Let its molecular formula be

It is given that **at STP 1L** of this gas weighs

So **at STP 22.4L** of this gas weighs

**So molar mass of the gas is**

*It is also given that on burning*

**1.5g of gas** produces **4.4g of CO2** and **2.7g of H2O**

So burning of **30g of gas**

produces

i.e.burning of **30g of gas** produces

i.e.burning of **1 mol of gas** produces

i.e.burning of **1molof gas** produces **2 mol of CO2 and 3 mol** of H2O

Now from equation (1) we see that

burning of **1 mol of gas** produces **x** mol of CO2 and

So comparing these two information we can say

**Hence the M F of Hydrocarbon is** **ETHANE**