# An electron in a mercury atom jumps from level #a# to level #g# by absorbing a single photon. How do you determine the energy of the photon in joules?

##### 1 Answer

May 22, 2017

Relativistic effects are present here... but I assume that the transition from level

- has
#DeltaL = pm 1# (the total change in angular momentum is exactly#1# ). - has
#DeltaS = 0# (no changing between spin-paired and spin-parallel). - is not influenced by relativistic effects (e.g. those that make one transition more favorable than another in cases of close-lying atomic orbitals, particularly big
#f# orbitals).

If that is the case, then since we only care about the photon...

#DeltaE = hnu#

...as long as you know the frequency of whatever light you chose in

I will not use the Rydberg equation, as it only works on hydrogen atom. Clearly, mercury has more than one electron, so it has nondegenerate orbitals of the same