# An ideal gas has a volume of 2.28 L at 279 K and 1.07 atm. What is the pressure when the volume is 1.03 L and the temperature is 307 K?

##### 1 Answer

#### Explanation:

First, we use the first set of data to calculate the **number of moles** using the **ideal gas equation**:

Where:

#"p"# is**pressure**in**pascals**(#"Pa"# )#"V"# is**volume**in**cubic metres**(#"m"^3# )#"n"# is the**number of moles**#"R"# is the**gas constant**=#8.314# #"T"# is the**temperature**in**Kelvin**(#"K"# )

First, convert your given values into workable units:

#1"L" = 0.001"m"^3, :. 2.28"L" = 0.00228"m"^3# #1"atm" = 101325"Pa", :. 1.07"atm" = 108417.8"Pa"#

Second, rearrange the equation to solve for **moles**:

Next, substitute in your given values and calculate the number of moles:

We can then move onto calculating the new pressure value. The first thing to do here is to, again, convert non-compliant units into ones that are accepted by the equation:

#1"L" = 0.001"m"^3, :. 1.03"L" = 0.00103"m"^3#

Then we rearrange the equation to solve for **pressure**:

And substituting in our values, we get: